2x^2+1x+8=0

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Solution for 2x^2+1x+8=0 equation:


Simplifying
2x2 + 1x + 8 = 0

Reorder the terms:
8 + 1x + 2x2 = 0

Solving
8 + 1x + 2x2 = 0

Solving for variable 'x'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
4 + 0.5x + x2 = 0

Move the constant term to the right:

Add '-4' to each side of the equation.
4 + 0.5x + -4 + x2 = 0 + -4

Reorder the terms:
4 + -4 + 0.5x + x2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 0.5x + x2 = 0 + -4
0.5x + x2 = 0 + -4

Combine like terms: 0 + -4 = -4
0.5x + x2 = -4

The x term is 0.5x.  Take half its coefficient (0.25).
Square it (0.0625) and add it to both sides.

Add '0.0625' to each side of the equation.
0.5x + 0.0625 + x2 = -4 + 0.0625

Reorder the terms:
0.0625 + 0.5x + x2 = -4 + 0.0625

Combine like terms: -4 + 0.0625 = -3.9375
0.0625 + 0.5x + x2 = -3.9375

Factor a perfect square on the left side:
(x + 0.25)(x + 0.25) = -3.9375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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